ERRATUM TO: HUGE CONTRACTION ON PARTIALLY ORDERED METRIC SPACES
نویسندگان
چکیده
منابع مشابه
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and Applied Analysis 3 Besides, if for any x, y ∈ M, there exists z ∈ M which is comparable to x and y, 2.4 then f has a unique fixed point. Proof. We first show that f has a fixed point. Since x0 f x0 and f is an increasing function, we obtain by induction that x0 f x0 f2 x0 f3 x0 · · · f x0 · · · . 2.5 Put xn 1 f x0 , n 1, 2, . . . For each integer n ≥ 1, from 2.5 , we have xn xn 1, then by 2...
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ژورنال
عنوان ژورنال: The Pure and Applied Mathematics
سال: 2016
ISSN: 1226-0657
DOI: 10.7468/jksmeb.2016.23.2.201